1.one

2.old

3.zero?

4.one?

1. 29

2. Old five

3. 0

4. 0

for #1 do you mean how many men? That's how I've heard this before.

Nope. Kharu-Kai, the last one is a math problem. Your answers need to be numbers.

1. One

2. Old

3. Zero

4. =1

I think thats right.

Nope.

1. Zero

2. Old five

3. Zero

4. Zero

Nope.

Go ahead and PM me your answers, KC.

Oh, wait change my first answer to one. Darn, I don't know why I wrote that.

Okay, but you're still wrong.

Wait, did each woman have seven sacks or they had a total of 7?

No, no. That one was right, but your others are wrong. Exept for the five. You have done well on the five.

~1~

As I was going to St Ives

I met a man with seven wives

Seven wives with seven sacks

Seven sacks with seven cats

Seven cats with seven kits

Kits, cats, sacks, wives

How many were going to St Ives?

~2~

Which is better, an old five-dollar bill or a new one?

~3~

From what number can you take half and leave nothing?

~4~

Answer to 1 + Answer to 3, – Answer to 2 x Answer to 3 = ___

1. 2

2. an old five-dollar bill

3. .5

4. 0

1. Right

2. Right (simplify so that it remains a single number)

3. WRONG

4. WRONG

Wait, why 2? You meet a man while going to St. Ives. It never stated the man was going to St. Ives.

Oops- wait. No. One is WRONG.

~1~

As I was going to St Ives

I met a man with seven wives

Seven wives with seven sacks

Seven sacks with seven cats

Seven cats with seven kits

Kits, cats, sacks, wives

How many were going to St Ives?

~2~

Which is better, an old five-dollar bill or a new one?

~3~

From what number can you take half and leave nothing?

~4~

Answer to 1 + Answer to 3, – Answer to 2 x Answer to 3 = ___

1.) 1 (The guy had all that stuff, but he didn't necessarily have it with him, and the guy wasn't necessarily going to St. Ives, so we only know of one guy going to St. Ives)

2.) 5 (An old $5, not new $1)

3.) 0 ( 0 x .5=0)

4.) 1 (Following the Order of Operations: 1+0-5x0= 1+0-0= 1)

Yes, yes, no, no.

For #3, look at a number where if you cut the number in half (the actual number, not the value) it looks like nothing.

1. One

2. Two

3. Eight

4. 24

1. Yes

2. No

3. Yes

4. No

1. One

2. Five

3. 8

4. 27

Nope. Go in accordance to PEMDAS (Order of Operations) for the last one.

But 1, 2, and 3 are correct.

1. One

2. Five

3. 8

4. 9

Is that right? PM if it is.

Close.... But no. Think PEMDAS.

I did that, and the awnser my calculater came up with is -31.

So, is it:

1. One

2. Five

3. 8

4. -31??